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3x^2+17x+20x=0
We add all the numbers together, and all the variables
3x^2+37x=0
a = 3; b = 37; c = 0;
Δ = b2-4ac
Δ = 372-4·3·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-37}{2*3}=\frac{-74}{6} =-12+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+37}{2*3}=\frac{0}{6} =0 $
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